x^2+4.5x+1=0

Solution for x^2+4.5x+1=0 equation:

x^2+4.5x+1=0

a = 1; b = 4.5; c = +1;
Δ = b2-4ac
Δ = 4.52-4·1·1
Δ = 16.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{16.25}}{2*1}=\frac{-4.5-\sqrt{16.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{16.25}}{2*1}=\frac{-4.5+\sqrt{16.25}}{2}
$